Aug 27, 2025 · We need to prove $$2 (a+b+c+d)\sqrt {\left (\left (\frac {a+b+c+d} {4}\right)^2-\frac {ab+ac+bc+ad+bd+cd} {6}\right)^3}\geq$$ $$\geq\tfrac { (a+b+c+d)^4} {32}-\tfrac { (a+b+c+d)^2 …

Nov 17, 2025 · ABCD is a landmark study on brain development and child health supported by the National Institutes of Health (NIH). This project will increase our understanding of environmental, …

Jul 21, 2025 · The ABCD Study is the largest long-term study of brain development and child and adolescent health in the U.S., enrolling nearly 12,000 youth beginning in 2016 when the youth were 9 …

Feb 3, 2025 · Question: In a square $ABCD$, the side length is given as: $$AB = 10$$ A point $E$ is taken on $AB$ such that: $$AE:EB = 2:3$$ Lines $DE$ and $BC$ are drawn, and they intersect at $F$.

Nov 21, 2022 · The Adolescent Brain Cognitive Development (ABCD) Study is the largest long-term study of brain and cognitive development in children across the United States ...

NIDA's mission is to advance science on the causes and consequences of drug use and addiction and to apply that knowledge to improve individual and public health. NIDA is one of the National Institutes …

Oct 27, 2025 · by the way recently you have posting geometry problem may I know the source of these problems?

Jul 11, 2025 · ABCD: Continuing the Arc of Development Join us at 9:00am ET on July 21-22 for our ABCD: Continuing the Arc of Development expert panel meeting. This 2-day public meeting will …

Sep 8, 2023 · Let $ABCD$ be a convex quadrilateral with $AD = BC$ and $∠A + ∠B = 120°$. Let $E$ be the midpoint of the side $CD$ and let $F$ and $G$ be the midpoints of the diagonals $AC$ and …

Jun 16, 2020 · In a given quadrilateral $ABCD$, we have $$AB = AD, \angle BAD = 60^\circ, \angle BCD = 120^\circ$$ Prove that $$ BC + DC = AC$$ I know the quadrilateral is cyclic.